How do you find the minimum value of a square root function #f(x)= 3-sqrt(x+2)#?

1 Answer
Jun 8, 2015

This one has no minimum value.

As #x# gets larger, the root gets larger, and the function as a whole becomes more and more negative (slowly but certainly).

Or, in "the language": #lim_(x->oo) f(x)=-oo#

It does have a maximum though:
The expression under the root may not be negative, it may be #0#. This happens when #x=-2->f(x)=3#
graph{3-sqrt(x+2) [-3.85, 47.45, -12.5, 13.2]}

Domain: #x>=-2#
Range: #f(x)<=3#