How do you find the number of complex, real and rational roots of $2 x^{2} + 5 x + 3 = 0$ $2x^2+5x+3=0$ ?

Question

1522 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-17T09:56:38

There are two rational roots $: - 1, - \frac{3}{2}$ $: -1, -3/2$ .

$2 x^{2} + 5 x + 3 = 0$ $2x^2+5x+3=0$

$:. ul(2x^2+2x)+ul(3x+3)=0$

$:. 2x(x+1)+3(x+1)=0$

$:. (x+1)(2x+3)=0$

$:. x=-1, or, x=-3/2$

Thus, there are two rational roots $: -1, -3/2$ .

How do you find the number of complex, real and rational roots of 2x^2+5x+3=02x2+5x+3=02x^2+5x+3=0?