# How do you find the perimeter and area of a right triangle with sides 3in, 4in, and 5in. the right angle is formed bye the two smaller sides?

$6$ sq. in.
Area of a triangle is $\frac{1}{2} \text{base" xx "height}$
With a right triangle the two non-hypotenuse sides form the $\text{base}$ and the $\text{height}$