How do you find the perimeter and area of an isosceles triangle with two equal sides of 10 feet, the base 16 feet,and the height 6 ft?

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Answer 1 · 2015-09-24T21:33:15

The perimeter is the sum of the lengths of the sides:

perimeter = #10"ft" + 10"ft" + 16"ft" = 36"ft"#

The area is #1/2 xx "base" xx "height" = 1/2 * 16"ft" * 6"ft" = 48 "ft"^2#

The perimeter of any polygon is the sum of the lengths of the sides.

The area of any triangle is #1/2 xx "base" xx "height"#