How do you find the perimeter and area of an isosceles triangle with two equal sides of 10 feet, the base 16 feet,and the height 6 ft?

Sep 24, 2015

The perimeter is the sum of the lengths of the sides:

perimeter = $10 \text{ft" + 10"ft" + 16"ft" = 36"ft}$

The area is $\frac{1}{2} \times {\text{base" xx "height" = 1/2 * 16"ft" * 6"ft" = 48 "ft}}^{2}$

Explanation:

The perimeter of any polygon is the sum of the lengths of the sides.

The area of any triangle is $\frac{1}{2} \times \text{base" xx "height}$