How do you find the perimeter of a square with a diagonal of 12 cm?

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Answer 1 · 2015-10-17T10:56:17

#24sqrt2#

diagonal of the square is #ssqrt2#

#ssqrt2# = #12#

#s# = #12/sqrt2#

having radical sign in the denominator is not in simplest form

#s# = #12/sqrt2# x #sqrt2/sqrt2#

= #12sqrt2/sqrt4#

= #12sqrt2/2#

= #6sqrt2#

perimeter of the square is #4s#

#4(6sqrt2)# = #24sqrt2#