Question

How do you find the perimeter of a triangle whose coordinates are (10,2) and (7,-3)?

Answer 1

Assuming the third coordinate is the origin `(0,0)`

Using the Pythagorean Theorem:

`color(white)("XXXX")`Distance `(0,0)` to `(10,2)`
`color(white)("XXXX")` `color(white)("XXXX")` `sqrt(10^2+2^2) = sqrt(104)`

`color(white)("XXXX")`Distance `(0,0)` to `(7,-3)`
`color(white)("XXXX")` `color(white)("XXXX")` `sqrt(7^2+(-3)^2) = sqrt(58)`

`color(white)("XXXX")`Distance `(10,2)` to `(7,-3)`
`color(white)("XXXX")` `color(white)("XXXX")` `sqrt(3^2+5^2) =sqrt(34)`

Perimeter = `sqrt(104) + sqrt(58)+sqrt(34)`

(perhaps this would have been a prettier answer with a third point other than the origin)