How do you find the period, amplitude and sketch #y=-0.1sin((pix)/10+pi)#?

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Answer 1 · 2017-03-03T09:51:59

#Amplitude=0.1#
#lambda= 20#

graph{y= -0.1 sin((pi/10)x+ pi) [-20, 20, -10, 10]}

#y= 0.1 sin((pi/10)x)##->##sin(pi+theta)= -sin(theta)#

Comparing with the standard form,

#y= A sin(omega t +- kx + phi) #

We get,

#Amplitude=0.1#

#k=pi/10#

#lambda= (2pi)/k#

#lambda= (2pixx10)/pi#

#lambda= (2cancelpixx10)/cancelpi#

#lambda= 20#