How do you find the period for #y=20cos((2/3)x+pi)+2#?
1 Answer
May 30, 2018
Explanation:
#"the standard form of the cosine function is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#
#"where amplitude "=|a|," period "=(2pi)/b#
#"phase shift "=-c/b" and vertical shift "=d#
#"here "b=2/3rArr"period "=(2pi)/(2/3)=3pi#