Question

How do you find the period of `2 sin 3x`?

Answer 1

I found: `(2pi)/3`

Explanation:

You can "read" the period using the `3` in the argument of the `sin`; the period will then be:
`"period=(2pi)/color(red)(3)`

Graphically:
graph{2sin(3x) [-10, 10, -5, 5]}

Your `sin` function will repear each `(2pi)/3` radians.