# How do you find the period of 2 sin 3x?

Jun 19, 2016

I found: $\frac{2 \pi}{3}$

#### Explanation:

You can "read" the period using the $3$ in the argument of the $\sin$; the period will then be:
"period=(2pi)/color(red)(3)

Graphically:
graph{2sin(3x) [-10, 10, -5, 5]}

Your $\sin$ function will repear each $\frac{2 \pi}{3}$ radians.