# How do you find the period of g(x)= (1/2cos2π/3)x?

##### 1 Answer
Sep 8, 2015

The period of the (corrected) function is $3$

#### Explanation:

Your original function is not trigonometric at all, so it does not have a period (it is just $x$ multiplied by an irrational constant $\frac{1}{2} \cos \left(\frac{2 \pi}{3}\right)$).

But I think you meant $y = \frac{1}{2} \cos \left(\frac{2 \pi}{3} x\right)$.

To calculate the period of such a function you divide the period if $\cos$ function by the coefficient of $x$, so the period is:

$T = \frac{2 \pi}{\frac{2 \pi}{3}} = \left(2 \pi\right) \cdot \left(\frac{3}{2 \pi}\right) = 3$