Question

How do you find the period of `g(x)= (1/2cos2π/3)x`?

Answer 1

The period of the (corrected) function is `3`

Explanation:

Your original function is not trigonometric at all, so it does not have a period (it is just `x` multiplied by an irrational constant `1/2cos((2pi)/3)`).

But I think you meant `y=1/2cos((2pi)/3x)`.

To calculate the period of such a function you divide the period if `cos` function by the coefficient of `x`, so the period is:

`T=(2pi)/((2pi)/3)=(2pi)*(3/(2pi))=3`