# How do you find the period of tan(2pi x) ?

Mar 19, 2018

See Below.

#### Explanation:

Standard form of equation is $y = A \tan \left(B x - C\right) + D$

Given $y = \tan \left(2 \pi x\right)$

$A m p l i t u \mathrm{de} = A = \text{None}$ Function $\tan x$ doesn't have an amplitude.

$\text{Period } = P = \frac{\pi}{|} B | = \frac{\pi}{2 \pi} = \frac{1}{2}$

$\text{ Phase Shift} = \frac{- C}{B} = \frac{0}{2 \pi} = 0$
$\text{Vertical Shift } = D = 0$

graph{tan(2pix) [-10, 10, -5, 5]}