How do you find the period of $tan(2pi x)$ ?

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Answer 1 · 2018-03-19T02:33:17

See Below.

Standard form of equation is $y = A tan (Bx - C) + D$

Given $y = tan (2pix)$

$Amplitude = A = "None"$ Function $tan x$ doesn't have an amplitude.

$"Period " = P = pi / |B| = pi/ (2pi) = 1/2$

$" Phase Shift" = (-C) / B = 0 / (2pi) = 0$
$"Vertical Shift " = D = 0$

graph{tan(2pix) [-10, 10, -5, 5]}

How do you find the period of tan(2pi x) tan(2pi x) ?