How do you find the period of #y=2 sin x#?

1 Answer
Dec 28, 2016

#"period " =2pi#

Explanation:

The standard form of the #color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period " =(2pi)/b#

#"phase shift " =-c/b, "vertical shift " =d#

#"here " a=2,b=1,c=0,d=0#

#rArr"period "=(2pi)/1=2pi#