How do you find the period, phase and vertical shift of #y=1/2csc3(theta-45^circ)+1#?
To find the period, look at k in the equation
The phase and vertical shift are also right in the equation as d and c.
In the equation, look for k, which in this case, is 3.
In degrees, it would be
The phase shift is also in the equation too, in which case you look for d. In this equation d is
Since it is a negative
The vertical shift is the last part of the equation: c, which is in this equation, 1 . If it is positive, it goes up. Negative shifts down. In this equation, the graph will shift up 1 unit.
Please correct me if I am wrong!