# How do you find the period, phase and vertical shift of #y=1/2csc3(theta-45^circ)+1#?

##### 1 Answer

To find the period, look at *k* in the equation

The phase and vertical shift are also right in the equation as *d* and *c.*

#### Explanation:

*Period:*

In the equation, look for *k*, which in this case, is *3.*

So:

In degrees, it would be

*Phase Shift:*

The phase shift is also in the equation too, in which case you look for *d*. In this equation *d* is

Since it is a negative

*Vertical Shift:*

The vertical shift is the last part of the equation: *c*, which is in this equation, *1* . If it is positive, it goes up. Negative shifts down. In this equation, the graph will shift up 1 unit.

Please correct me if I am wrong!