# How do you find the period, phase and vertical shift of y=4sec2(theta+pi/2)-3?

May 31, 2018

As explained

#### Explanation:

Standard form of secant function is

$y = A \sec \left(B x - C\right) + D$

Guven : $y = 4 \sec \left(2 \theta + \pi\right) - 3$

Amplitude for secant function - None

Period $= \frac{\pi}{|} B | = \frac{2 \pi}{2} = \pi$

Phase Shift $= - \frac{C}{B} = - \frac{\pi}{2} ,$pi/2# to the left

Vertical Shift $= D = - 3$