# How do you find the point on the unit circle that corresponds to pi/4?

$P \left(\frac{\sqrt{2}}{2} , \frac{\sqrt{2}}{2}\right)$
In the unit circle, all points are of the form $\left(\cos \left(\theta\right) , \sin \left(\theta\right)\right)$ where $\theta$ is the angle made with the x-axis on the first quadrant, which, in this case is $\frac{\pi}{4}$ radians, or (180º)/4 = 45º
So now we just take the cosine, and the sine. Since 45º is a special angle, we already know those values, and can just say
$P \left(\frac{\sqrt{2}}{2} , \frac{\sqrt{2}}{2}\right)$