Question

How do you find the points of horizontal tangency of `r=2cos(3theta-2)`?

Answer 1

The slope, m, of a Tangent to a Polar Curve is found using the equation:

`m = ((dr)/(d theta)sin(theta)+rcos(theta))/((dr)/(d theta)cos(theta)-rsin(theta))`

The point of is of tangency is:

`(rcos(theta),rsin(theta))`