# How do you find the points of horizontal tangency of r=2cos(3theta-2)?

$m = \frac{\frac{\mathrm{dr}}{d \theta} \sin \left(\theta\right) + r \cos \left(\theta\right)}{\frac{\mathrm{dr}}{d \theta} \cos \left(\theta\right) - r \sin \left(\theta\right)}$
$\left(r \cos \left(\theta\right) , r \sin \left(\theta\right)\right)$