How do you find the polar equation for $3x-2y=1$ ?

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Answer 1 · 2016-11-08T18:44:10

The polar equation is $r=1/(3costheta-2sintheta)$

We use, $x=rcostheta$ and $y=rsintheta$ , to go from cartesian to polar coordinates.

$3x-2y=1$ $=>$ $3rcostheta-2rsintheta=1$

$r=1/(3costheta-2sintheta)$

Answer 2 · 2016-11-08T18:45:06

$rho=1/(3cos(theta)-2sin(theta))$

$x=rhocos(theta)$
$y=rhosin(theta)$
$rho=root2(x^2+y^2)$

$3rhocos(theta)-2rhosin(theta)=1$
$rho=1/(3cos(theta)-2sin(theta))$

How do you find the polar equation for 3x-2y=13x-2y=1?