# How do you find the polynomial function with roots 11 and 2i?

Jul 23, 2015

I'll show you how below.

#### Explanation:

Start by writing,

$x = 11$
Thus, $x - 11 = 0$

Also, $x = 2 i$
Therefore, $x - 2 i = 0$

Now, $\left(x - 11\right) \left(x - 2 i\right) = 0$
$\implies$ ${x}^{2} - 2 x i - 11 x + 22 i = 0$