One x-intercept for a parabola is at the point (1,0). How do you use the factor method to find the other x- intercept for the parabola defined by this equation: $y = 2 x^{2} + 8 x - 10$ $y=2x^2+8x-10$ ?

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Answer 1 · 2016-10-30T21:43:48

The second $x$ $x$ -intercept is at $(- 5, 0)$ $(-5, 0)$

The $x$ $x$ -intercepts occur when $y = 0$ $y = 0$ .

$0 = 2 x^{2} + 8 x - 10$ $0 = 2x^2 + 8x - 10$

$0 = 2 (x^{2} + 4 x - 5)$ $0 = 2(x^2 + 4x - 5)$

$0 = x^{2} + 4 x - 5$ $0 = x^2 + 4x - 5$

$0 = (x + 5) (x - 1)$ $0 = (x + 5)(x -1)$

$x = - 5 AND 1$ $x = -5" AND " 1$

Hence, the x intercepts are at $(- 5, 0)$ $(-5, 0)$ and $(1, 0)$ $(1, 0)$ .

Hopefully this helps!

One x-intercept for a parabola is at the point (1,0). How do you use the factor method to find the other x- intercept for the parabola defined by this equation: y=2x^2+8x-10y=2x2+8x−10y=2x^2+8x-10?