# One x-intercept for a parabola is at the point (1,0). How do you use the factor method to find the other x- intercept for the parabola defined by this equation: y=2x^2+8x-10?

Oct 30, 2016

The second $x$-intercept is at $\left(- 5 , 0\right)$

#### Explanation:

The $x$-intercepts occur when $y = 0$.

$0 = 2 {x}^{2} + 8 x - 10$

$0 = 2 \left({x}^{2} + 4 x - 5\right)$

$0 = {x}^{2} + 4 x - 5$

$0 = \left(x + 5\right) \left(x - 1\right)$

$x = - 5 \text{ AND } 1$

Hence, the x intercepts are at $\left(- 5 , 0\right)$ and $\left(1 , 0\right)$.

Hopefully this helps!