How do you find the product #(11z-5y)(3z+2y)#?

1 Answer
Jan 14, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(11z) - color(red)(5y))(color(blue)(3z) + color(blue)(2y))# becomes:

#(color(red)(11z) xx color(blue)(3z)) + (color(red)(11z) xx color(blue)(2y)) - (color(red)(5y) xx color(blue)(3z)) - (color(red)(5y) xx color(blue)(2y))#

#33z^2 + 22zy - 15zy - 10y^2#

We can now combine like terms:
#33z^2 + (22 - 15)zy - 10y^2#

#33z^2 + 7zy - 10y^2#