# How do you find the product (2m+3)(2m-3)(m+4)?

Jun 22, 2017

$4 {m}^{3} - 16 {m}^{2} - 9 m - 36$
$\left(2 m + 3\right) \left(2 m - 3\right)$ is a difference of squares so you can either F.O.I.L. or use difference of squares$= \left(4 {m}^{2} - 9\right)$
next multiply by the remaining factor $\left(m + 4\right)$
$\left(4 {m}^{2} - 9\right) \left(m + 4\right)$ foiled equals $4 {m}^{3} - 16 {m}^{2} - 9 m - 36$