How do you find the product #(2n+3)(n+9)#?
1 Answer
Apr 26, 2017
Explanation:
Each term in the second bracket is multiplied by each term in the first bracket as shown below.
#(color(red)(2n+3))(n+9)#
#=color(red)(2n)(n+9)color(red)(+3)(n+9)#
#=(color(red)(2n)xxn)+(color(red)(2n)xx9)+(color(red)(3)xxn)+(color(red)(3)xx9)#
#=2n^2+18n+3n+27#
#=2n^2+21n+27#
