Question

How do you find the product `(2n+3)(n+9)`?

Answer 1

`2n^2+21n+27`

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

`(color(red)(2n+3))(n+9)`

`=color(red)(2n)(n+9)color(red)(+3)(n+9)`

`=(color(red)(2n)xxn)+(color(red)(2n)xx9)+(color(red)(3)xxn)+(color(red)(3)xx9)`

`=2n^2+18n+3n+27`

`=2n^2+21n+27`