# How do you find the product (2n+3)(n+9)?

Apr 26, 2017

$2 {n}^{2} + 21 n + 27$

#### Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

$\left(\textcolor{red}{2 n + 3}\right) \left(n + 9\right)$

$= \textcolor{red}{2 n} \left(n + 9\right) \textcolor{red}{+ 3} \left(n + 9\right)$

$= \left(\textcolor{red}{2 n} \times n\right) + \left(\textcolor{red}{2 n} \times 9\right) + \left(\textcolor{red}{3} \times n\right) + \left(\textcolor{red}{3} \times 9\right)$

$= 2 {n}^{2} + 18 n + 3 n + 27$

$= 2 {n}^{2} + 21 n + 27$