How do you find the product #(3c-5)(c+3)#?

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Answer 1 · 2017-05-17T12:16:59

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3c) - color(red)(5))(color(blue)(c) + color(blue)(3))# becomes:

#(color(red)(3c) xx color(blue)(c)) + (color(red)(3c) xx color(blue)(3)) - (color(red)(5) xx color(blue)(c)) - (color(red)(5) xx color(blue)(3))#

#3c^2 + 9c - 5c - 15#

We can now combine like terms:

#3c^2 + (9 - 5)c - 15#

#3c^2 + 4c - 15#