# How do you find the product (3t+12)(3t-12)?

May 20, 2017

See a solution process below:

#### Explanation:

This is a special form:

$\left(a + b\right) \left(a - b\right) = {a}^{2} - {b}^{2}$

Substituting $3 t$ for $a$ and $12$ for $b$ gives:

$\left(3 t + 12\right) \left(3 t - 12\right) \implies {\left(3 t\right)}^{2} - {12}^{2} \implies 9 {t}^{2} - 144$