How do you find the product #(5r+7)(5r-7)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer ali ergin Feb 16, 2017 #(5r+7)(5r-7)=25r^2-49# Explanation: #color (red)((x-a)(x+a)=x^2-a^2)# #(5r+7)(5r-7)=(5r)^2-(7)^2=25r^2-49# #"or"# #(5r+7)(5r-7)=5r*5r-5r*7+7*5r-7*7# #(5r+7)(5r-7)=25r^2cancel(-35r)cancel(+35r)-49# #(5r+7)(5r-7)=25r^2-49# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 3049 views around the world You can reuse this answer Creative Commons License