How do you find the product #(6y-7)(6y+7)#?

1 Answer
Apr 22, 2017

Answer:

#36y^2-49#

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket. This can be achieved as follows.

#(color(red)(6y-7))(6y+7)#

#=color(red)(6y)(6y+7)color(red)(-7)(6y+7)#

#=(color(red)(6y)xx6y)+(color(red)(6y)xx7)+(color(red)(-7)xx6y)+(color(red)(-7)xx7)#

#=36y^2+42y-42y-49#

#=36y^2-49larrcolor(magenta)" difference of squares"#