# How do you find the product (8-10a)^2?

Jun 30, 2017

See a solution process below:

#### Explanation:

This is a special for of a quadratic where:

${\left(a - b\right)}^{2} = {a}^{2} - 2 a b + {b}^{2}$

Substituting:

$8$ for $a$

$10 a$ for $b$

Gives:

${\left(8 - b\right)}^{2} = {8}^{2} - \left(2 \cdot 8 \cdot 10 a\right) + {\left(10 a\right)}^{2} =$

$64 - 160 a + 100 {a}^{2}$

Or, in standard polynomial form:

$100 {a}^{2} - 160 a + 64$