How do you find the product (8w+4x)(5w-6x)?

Jan 8, 2017

See full process description below:

Explanation:

First, cross multiply each term in the left parenthesis by each term in the right parenthesis:

$\left(\textcolor{red}{8 w} + \textcolor{red}{4 x}\right) \left(\textcolor{b l u e}{5 w} - \textcolor{b l u e}{6 x}\right)$

$\left(\textcolor{red}{8 w} \times \textcolor{b l u e}{5 w}\right) - \left(\textcolor{red}{8 w} \times \textcolor{b l u e}{6 x}\right) + \left(\textcolor{red}{4 x} \times \textcolor{b l u e}{5 w}\right) - \left(\textcolor{red}{4 x} \times \textcolor{b l u e}{6 x}\right)$

$40 {w}^{2} - 48 w x + 20 w x - 24 {x}^{2}$

Now we can combine like terms to finalize the calculation:

$40 {w}^{2} + \left(- 48 + 20\right) w x - 24 {x}^{2}$

$40 {w}^{2} + \left(- 28\right) w x - 24 {x}^{2}$

$40 {w}^{2} - 28 w x - 24 {x}^{2}$