How do you find the product #(c+9)(c-3)#?

Question

2355 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-20T14:10:11

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(c) + color(red)(9))(color(blue)(c) - color(blue)(3))# becomes:

#(color(red)(c) xx color(blue)(c)) - (color(red)(c) xx color(blue)(3)) + (color(red)(9) xx color(blue)(c)) - (color(red)(9) xx color(blue)(3))#

#c^2 - 3c + 9c - 27#

We can now combine like terms:

#c^2 + (-3 + 9)c - 27#

#c^2 + 6c - 27#