# How do you find the product (d+4)(d+10)?

May 3, 2017

${d}^{2} + 14 d + 40$

#### Explanation:

When you multiply terms in your equation, you will obtain:

$\left(d \cdot d\right) + \left(10 \cdot d\right) + \left(4 \cdot d\right) + \left(4 \cdot 10\right)$

or

${d}^{2} + 14 d + 40$

${d}^{2} + 14 d + 40$
If d=3, you will get $91$ from the aforegiven equation
From the original equation (on the question) $7 \cdot 13$ you will get the same result $91$