How do you find the product #(d+4)(d+10)#?

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Answer 1 · 2017-05-03T09:25:56

#d^2+14d+40#

When you multiply terms in your equation, you will obtain:

#(d*d) + (10*d) + (4*d) + (4*10)#

or

#d^2 + 14 d + 40#

It is your answer:

#d^2 + 14d + 40#

If d=3, you will get #91# from the aforegiven equation

From the original equation (on the question) #7*13# you will get the same result #91#