Question

How do you find the product of `(2n-7)^2`?

Answer 1

`=(2n-7)^2=4n^2-28n+49.`

Explanation:

Reqd. Product`=(2n-7)^2=(2n-7)*(2n-7)=2n(2n-7)-7(2n-7)...[Distributive Law] = 4n^2-14n-14n+49=4n^2-28n+49.`

OR, we can use the formula, `(a-b)^2=a^2-2ab+b^2,` & get,
The product`=(2n)^2-2*2n*7+7^2=4n^2-28n+49,` as before!