How do you find the product of $- 3 + \sqrt{2 i}$ $-3 + sqrt(2i)$ and its conjugate?

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How do you find the product of $- 3 + \sqrt{2 i}$ $-3 + sqrt(2i)$ and its conjugate?

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Answer 1 · 2016-10-21T19:03:03

The product of any complex number, $a + b i$ $a + bi$ and its conjugate is always $a^{2} + b^{2}$ $a^2 + b^2$ . In your case, ${(- 3)}^{2} + {(\sqrt{2})}^{2} = 11$ $(-3)^2 + (sqrt(2))^2 = 11$

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How do you find the product of $- 3 + \sqrt{2 i}$ $-3 + sqrt(2i)$ and its conjugate?

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