How do you find the product of #(3c+1)(c-2)#?

1 Answer
Sep 2, 2016

Answer:

#3c^2-5c-2#

Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.
We can obtain this as follows.

#(color(red)(3c+1))(c-2)=color(red)(3c)(c-2)color(red)(+1)(c-2)#

now distribute the brackets and collect like terms.

#=3c^2-6c+c-2=3c^2-5c-2#

#rArr(3c+1)(c-2)=3c^2-5c-2#