# How do you find the product of (3c+1)(c-2)?

Sep 2, 2016

$3 {c}^{2} - 5 c - 2$

#### Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.
We can obtain this as follows.

$\left(\textcolor{red}{3 c + 1}\right) \left(c - 2\right) = \textcolor{red}{3 c} \left(c - 2\right) \textcolor{red}{+ 1} \left(c - 2\right)$

now distribute the brackets and collect like terms.

$= 3 {c}^{2} - 6 c + c - 2 = 3 {c}^{2} - 5 c - 2$

$\Rightarrow \left(3 c + 1\right) \left(c - 2\right) = 3 {c}^{2} - 5 c - 2$