# How do you find the product of (3n-7)(n+3)?

$3 {n}^{2} + 2 n - 21$
$\left(3 n - 7\right) \left(n + 3\right) = 3 n \cdot n + 3 n \cdot 3 + \left(- 7\right) \cdot n + \left(- 7\right) \cdot 3 = 3 {n}^{2} + 2 n - 21$