How do you find the product of #(4a+7)^2#?

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Answer 1 · 2017-07-14T13:17:42

See a solution process below:

We can use this special rule of a quadratic to simplify this expression:

#(x + y)^2 = x^2 + 2xy + y^2#

Substituting:

#4a# for #x# and #7# for #y# gives:

#(4a + 7)^2 =>#

#(4a)^2 + (2 * 4a * 7) + 7^2 =>#

#16a^2 + 56a + 49#