How do you find the product of #(4h-2)(4h-1)#?

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Answer 1 · 2017-07-15T21:49:04

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4h) - color(red)(2))(color(blue)(4h) - color(blue)(1))# becomes:

#(color(red)(4h) xx color(blue)(4h)) - (color(red)(4h) xx color(blue)(1)) - (color(red)(2) xx color(blue)(4h)) + (color(red)(2) xx color(blue)(1))#

#16h^2 - 4h - 8h + 2#

We can now combine like terms:

#16h^2 + (-4 - 8)h + 2#

#16h^2 + (-12)h + 2#

#16h^2 - 12h + 2#