How do you find the product of (4h-2)(4h-1)?

Jul 15, 2017

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{4 h} - \textcolor{red}{2}\right) \left(\textcolor{b l u e}{4 h} - \textcolor{b l u e}{1}\right)$ becomes:

$\left(\textcolor{red}{4 h} \times \textcolor{b l u e}{4 h}\right) - \left(\textcolor{red}{4 h} \times \textcolor{b l u e}{1}\right) - \left(\textcolor{red}{2} \times \textcolor{b l u e}{4 h}\right) + \left(\textcolor{red}{2} \times \textcolor{b l u e}{1}\right)$

$16 {h}^{2} - 4 h - 8 h + 2$

We can now combine like terms:

$16 {h}^{2} + \left(- 4 - 8\right) h + 2$

$16 {h}^{2} + \left(- 12\right) h + 2$

$16 {h}^{2} - 12 h + 2$