How do you find the product of #(4u+9v)^2#?

1 Answer
Dec 19, 2016

Answer:

#16u^2+72uv+81v^2#

Explanation:

write as:#" "color(blue)((4u+9v))color(brown)((4u+9v))#

Multiply everything inside the right hand brackets by everything in the left hand brackets.

#color(brown)(color(blue)(4u)(4u+9v)color(blue)(" "+" "9v)(4u+9v) )#

#16u^2+36vu" "+" "36vu+81v^2#

#16u^2+72uv+81v^2#