# How do you find the product of (4u+9v)^2?

Dec 19, 2016

$16 {u}^{2} + 72 u v + 81 {v}^{2}$

#### Explanation:

write as:$\text{ } \textcolor{b l u e}{\left(4 u + 9 v\right)} \textcolor{b r o w n}{\left(4 u + 9 v\right)}$

Multiply everything inside the right hand brackets by everything in the left hand brackets.

$\textcolor{b r o w n}{\textcolor{b l u e}{4 u} \left(4 u + 9 v\right) \textcolor{b l u e}{\text{ "+" } 9 v} \left(4 u + 9 v\right)}$

$16 {u}^{2} + 36 v u \text{ "+" } 36 v u + 81 {v}^{2}$

$16 {u}^{2} + 72 u v + 81 {v}^{2}$