How do you find the product of (-6x-7y^2)^2?

2 Answers
Apr 11, 2018

The final product is 36x^2+84xy^2+49y^4.

Explanation:

First, you can factor out a negative one:

color(white)=(-6x-7y^2)^2

=(-1*(6x+7y^2))^2

=(-1)^2*(6x+7y^2)^2

=1*(6x+7y^2)^2

=(6x+7y^2)^2

Then, write out the actual multiplication:

=(6x+7y^2)(6x+7y^2)

Now, multiply each combination of the factors (called FOIL method):

=6x*6x+6x*7y^2+7y^2*6x+7y^2*7y^2

=36x^2+42xy^2+42xy^2+49y^4

=36x^2+84xy^2+49y^4

That's the product. Hope this helped!

Apr 11, 2018

(-6x-7y^2)^2=color(blue)(36x^2+84xy^2+49y^4

Explanation:

Given:

(-6x-7y^2)^2

Use the square of a difference:

(a-b)^2=a^2-2ab+b^2,

where:

a=-6x, and b=7y^2.

(-6x-7y^2)^2=

(-6x)^2-2(-6x)(7y^2)+(7y^2)^2

Simplify.

36x^2+84xy^2+49y^4