How do you find the product of #(8a^2-2)(8a^2+2)#?

1 Answer
Jan 23, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8a^2) - color(red)(2))(color(blue)(8a^2) + color(blue)(2))# becomes:

#(color(red)(8a^2) xx color(blue)(8a^2)) + (color(red)(8a^2) xx color(blue)(2)) - (color(red)(2) xx color(blue)(8a^2)) - (color(red)(2) xx color(blue)(2))#

#64a^4 + 16a^2 - 16a^2 - 4#

We can now combine like terms:

#64a^4 + (16 - 16)a^2 - 4#

#64a^4 - 4#