# How do you find the product of (8r-1)(r-6)?

Aug 13, 2017

$\left(8 r - 1\right) \left(r - 6\right) = 8 {r}^{2} - 49 r + 6$

#### Explanation:

If you find it helpful, you can use the FOIL mnemonic to remember all the combinations of terms to multiply:

$\left(8 r - 1\right) \left(r - 6\right) = {\overbrace{\left(8 r\right) \left(r\right)}}^{\text{First"+overbrace((8r)(-6))^"Outside"+overbrace((-1)(r))^"Inside"+overbrace((-1)(-6))^"Last}}$

$\textcolor{w h i t e}{\left(8 r - 1\right) \left(r - 6\right)} = 8 {r}^{2} - 48 r - r + 6$

$\textcolor{w h i t e}{\left(8 r - 1\right) \left(r - 6\right)} = 8 {r}^{2} - 49 r + 6$