How do you find the product of #(8x^2 + 6y + 8) (y + 6) #?

1 Answer
Feb 27, 2017

Answer:

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8x^2) + color(red)(6y) + color(red)(8))(color(blue)(y) + color(blue)(6))# becomes:

#(color(red)(8x^2) xx color(blue)(y)) + (color(red)(8x^2) xx color(blue)(6)) + (color(red)(6y) xx color(blue)(y)) + (color(red)(6y) xx color(blue)(6)) + (color(red)(8) xx color(blue)(y)) + (color(red)(8) xx color(blue)(6))#

#8x^2y + 48x^2 + 6y^2 + 36y + 8y + 48#

We can now combine like terms:

#8x^2y + 48x^2 + 6y^2 + (36 + 8)y + 48#

#8x^2y + 48x^2 + 6y^2 + 44y + 48#