Question

How do you find the product of `(8x + 7)(x + 2)`?

Answer 1

`8x^2+23x+14`

Explanation:

`(8x+7)(x+2)`
First, we will distribute parentheses/brackets
from `(8x+7)(x+2)` to
`8x*x+8x*2+7*x+7*2`
Example:
`(w+x)(y+z)=wy+wz+xy+xz`
In this case, `w` would be `8x`, `x` would be `7`, `y` would be `x` and `z` would be `2`.

`8x*x+8x*2+7*x+7*2` is the same as
`8x x+8x*2+7x+7*2`
Now we will do:
`8x^2+8x*2+7x+7*2`
Why did `8x x` change to `8x^2`?
It's because of this:
`aa = a^(1+1)=a^2`

So, now you have `8x^2+8x*2+7x+7*2`
You want to solve bit by bit. First we'll start with `8x*2`. `8*2=16` So we can replace `8x*2` with `16x`.
`8x^2+16x+7x+7*2`
`16x+7x=23x`
`8x^2+23x+7*2`
`7*2=14`

`8x^2+23x+14`
That's your answer! ^