# How do you find the product of all six trigonometric functions of an angle theta in standard position whose terminal side passes through (- sqrt 3, 1)?

Dec 9, 2016

Find values of trig functions

#### Explanation:

Consider the right triangle OMm with
$O m = - \sqrt{3}$; and Mn = 1.
The hypotenuse OM equals to: $O M = \sqrt{1 + 3} = 2$
Call t the angle < Mom.
$\sin t = \frac{1}{2}$
$\cos t = \frac{\sqrt{3}}{2}$
$\tan t = \sin \frac{t}{\cos t} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}$
$\cot t = \sqrt{3}$
$\sec t = \frac{2}{\sqrt{3}} = 2 \frac{\sqrt{3}}{3}$
$\csc t = 2$