Question

How do you find the product of each complex number `8-2i` and its conjugate?

Answer 1

I found `68`

Explanation:

The conjugade is: `8+2i`
so you have:
`(8-2i)(8+2i)=` use the distributive property:
`=(8*8)+(2*8)i-(2*8)i-(2*2)(i*i)=`
`=64+cancel((2*8)i)cancel(-(2*8)i)-4i^2=`
but:
`i^2=(sqrt(-1))^2=-1`
so:
`64+4=68` a Pure Real!!!