How do you find the product of #(h-2)(3h-5)#?

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Answer 1 · 2018-03-11T22:02:51

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(h) - color(red)(2))(color(blue)(3h) - color(blue)(5))# becomes:

#(color(red)(h) xx color(blue)(3h)) - (color(red)(h) xx color(blue)(5)) - (color(red)(2) xx color(blue)(3h)) + (color(red)(2) xx color(blue)(5))#

#3h^2 - 5h - 6h + 10#

We can now combine like terms:

#3h^2 + (-5 - 6)h + 10#

#3h^2 + (-11)h + 10#

#3h^2 - 11h + 10#