How do you find the product of #(n-4)(n+2)(n+1)#?

1 Answer
Apr 2, 2017

Answer:

#n^3-n^2-10n-8#

Explanation:

#"Given factors of the form " (n+a)(n+b)(n+c)#

#"We can expand using the method"#

#n^3+(a+b+c)n^2+(ab+bc+ac)n+abc#

#"here " a=-4,b=2" and c=1#

#rArrn^3+(-4+2+1)n^2+(-8+2-4)n+(-4xx2xx1)#

#=n^3-n^2-10n-8larrcolor(red)" is the product"#