How do you find the product of #(n-4)(n+2)(n+1)#?
1 Answer
Apr 2, 2017
Explanation:
#"Given factors of the form " (n+a)(n+b)(n+c)#
#"We can expand using the method"#
#n^3+(a+b+c)n^2+(ab+bc+ac)n+abc#
#"here " a=-4,b=2" and c=1#
#rArrn^3+(-4+2+1)n^2+(-8+2-4)n+(-4xx2xx1)#
#=n^3-n^2-10n-8larrcolor(red)" is the product"#
