# How do you find the product of (t+2)(t+9)?

Jun 20, 2018

${t}^{2} + 11 t + 18$

Here's how I did it:

#### Explanation:

$\left(t + 2\right) \left(t + 9\right)$

To simplify this, we will use the distributive method called FOIL:

Following this image, we can multiply it out.

The $\textcolor{t e a l}{\text{firsts}}$:
$\textcolor{t e a l}{t \cdot t} = {t}^{2}$

The $\textcolor{\in \mathrm{di} g o}{\text{outers}}$:
$\textcolor{\in \mathrm{di} g o}{t \cdot 9} = 9 t$

The $\textcolor{p e r u}{\text{inners}}$:
$\textcolor{p e r u}{2 \cdot t} = 2 t$

The $\textcolor{o l i v e \mathrm{dr} a b}{\text{lasts}}$:
$\textcolor{o l i v e \mathrm{dr} a b}{2 \cdot 9} = 18$

${t}^{2} + 9 t + 2 t + 18$
We can still combine the like terms $9 t$ and $2 t$, so the final simplification is:
${t}^{2} + 11 t + 18$