How do you find the product of #(t+2)(t+9)#?

1 Answer
Jun 20, 2018

Answer:

#t^2 + 11t + 18#

Here's how I did it:

Explanation:

#(t+2)(t+9)#

To simplify this, we will use the distributive method called FOIL:
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Following this image, we can multiply it out.

The #color(teal)("firsts")#:
#color(teal)(t*t) = t^2#

The #color(indigo)("outers")#:
#color(indigo)(t*9) = 9t#

The #color(peru)"inners"#:
#color(peru)(2*t) = 2t#

The #color(olivedrab)"lasts"#:
#color(olivedrab)(2*9) = 18#

Combine them all together to get your answer:
#t^2 + 9t + 2t + 18#

We can still combine the like terms #9t# and #2t#, so the final simplification is:
#t^2 + 11t + 18#

Hope this helps!