# How do you find the product of the complex number and its conjugate of -7+sqrt(13i)?

##### 1 Answer
Dec 30, 2015

$62$

#### Explanation:

The given complex number is $- 7 + i \sqrt{13}$
The conjugate of the given number is $- 7 - i \sqrt{13}$

The product=$\left(- 7 + i \sqrt{13}\right) \left(- 7 - i \sqrt{13}\right) = {\left(- 7\right)}^{2} - {\left(i \sqrt{13}\right)}^{2} = 49 - 13 {i}^{2} = 49 - \left(- 13\right) = 49 + 13 = 62$