How do you find the product of $(x-y)(2x-y)$ ?

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Answer 1 · 2017-08-08T23:41:35

$2x^2 - 3xy + y^2$

Given: $(x-y)(2x-y)$

To multiply use FOIL and distribute $(a + b)(c + d) = ac + ad + bc + bd)$ :

$(x-y)(2x-y) = 2x x -xy -2xy + yy$

Also remember that $x * x = x^1 * x^1 = x^(1+1) = x^2$

$2x x -xy -2xy +(- y)(-y) = 2x^2 - 3xy + y^2$

So, $(x-y)(2x-y) = 2x^2 - 3xy + y^2$

How do you find the product of (x-y)(2x-y)(x-y)(2x-y)?