# How do you find the product of (x-y)(2x-y)?

Aug 8, 2017

$2 {x}^{2} - 3 x y + {y}^{2}$

#### Explanation:

Given: $\left(x - y\right) \left(2 x - y\right)$

To multiply use FOIL and distribute (a + b)(c + d) = ac + ad + bc + bd):

$\left(x - y\right) \left(2 x - y\right) = 2 x x - x y - 2 x y + y y$

Also remember that $x \cdot x = {x}^{1} \cdot {x}^{1} = {x}^{1 + 1} = {x}^{2}$

$2 x x - x y - 2 x y + \left(- y\right) \left(- y\right) = 2 {x}^{2} - 3 x y + {y}^{2}$

So, $\left(x - y\right) \left(2 x - y\right) = 2 {x}^{2} - 3 x y + {y}^{2}$