# How do you find the product of (y + 8) (y + 6) ?

May 3, 2018

${y}^{2} + 14 x + 48$

#### Explanation:

To multiply the binomials $\left(y + 8\right) \left(y + 6\right)$
we would incorporate the FOIL

F = Firsts
O = Outers
I = Inners
L = Lasts

Multiplying the Firsts $y \cdot y$
Multiplying the Outers $+ 6 \cdot y$ and $+ 8 \cdot y$
Multiplying the Lasts $\left(+ 8\right) \cdot \left(+ 6\right)$

We get
${y}^{2} + 6 y + 8 y + 48$

${y}^{2} + 14 x + 48$